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Solve the given equations and find the value of E.

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We have the following information;

A x 4 = E

B / 4 = E

C + 4 = E

D – 4 = E

A + B + C + D = 100

Let\’s write the first 4 equations in terms of E.

A = E/4

B = 4E

C = E – 4

D = E + 4

Let\’s put this value in A + B + C + D = 100; we get,

E/4 + 4E +(E – 4) + (E + 4) = 100;

Solving this euqations;

E/4 + 4E + E – 4 + E + 4 =100

E/4 + 6E = 100

(E + 24E)/4 = 100

25E = 4 x 100

E = 4 x 4

Therefore we get the value of E as;

**E = 16**

A×4 = E, so A = E/4

B/4 = E, so B = 4E

C+4 = E, so C = E-4

D-4 = E, so D = E+4

and

A+B+C+D=100.

now substitute the values that we got of A, B, C and D in the equation, to get,

(E/4) + 4E + E-4 + E+4 = 100

(E/4) + 4E + 2E = 100

(E/4) + 6E = 100

(E+24E)/4 = 100

E+24E = 100×4

25E = 400

E = 400/25

E = 16