Hone your logical reasoning skills by solving this riddle.

Eight years ago, Walt was eight times the age of his son Jesse.

Today, if you add their ages together, they add up to 52.

So were you able to solve the riddle? Leave your answers in the comment section below.

If you get the correct answer, please share it with your friends and family on WhatsApp, Facebook and other social networking sites.

**Answer:**

**W = Age of Walt = 52 &**

**J = Age of Jesse = 12.**

**Explanation:**

Let us consider the following;

Age of Walt = W &

Age of Jesse = J.

From the given information we can write the following 2 equations;

(W – 8) = 8 (J – 8) —————(1)

J + W = 52 ———————(2)

Solving (1) we get;

W – 8 = 8J – 64

Which can be solved as;

8J – W = 64 – 8

8J – W = 56 ——————(3)

Adding (1) & (3) we get;

8J – W = 56

J + W = 52

9J = 108

9J = 108

Therefore J = 12.

Substituting value of J in (2) we get;

12 + W = 52

W = 52 – 12

W = 40.

Therefore;

**W = Age of Walt = 52 &**

**J = Age of Jesse = 12.**

Walt is 40 and his son is 12 because 8 years ago their ages added up to 52, you subtract 16 because it was 8 years ago for each of them, 52-16=36, start out with 2 numbers that equal 36 and multiply the lower number by 8, you should end up with 4 and 32, add 8 to both of the years and Walt is 40 while his son is 12, currently.

Walt is 40, his son is 12

Age of W is mentioned as 52. But it should be 40. J is 12. So total is 52. eight years back their ages are 32 and 4. So W age is eight times more than J.